Aider moi svp a résoudre: x^2(x+3)=0 3x(2x+5)=0 5x^2+12x=0

Bonsoir

x^2(x+3)=0

x² = 0            ou             x + 3 = 0

                                             x = -3

S = {0;-3}

 
 3x(2x+5)=0

3x = 0   

x = 0             ou          2x + 5 = 0

                                              2x = - 5

                                                x = -5/2

 5x^2+12x=0

x(5x+12) = 0

x = 0   ou      5x + 12 = 0

                              5x = -12

                                 x = -12/5

S = {0;-12/5}