ces deux calcule svp 7x²-5x=0 (3x++1)(x-4)=2x(x-4)

7x² - 5x = 0
x(7x - 5) = 0
x = 0
ou
7x - 5 = 0
7x = - 5
x = - 5/7

(- 3x + 1)(x - 4) = 2x(x - 4)
(- 3x + 1)(x - 4) - 2x(x - 4)  = 0
(x - 4)(- 3x + 1 - 2x) = 0
(x - 4)(- 5x + 1) = 0
x - 4 = 0
x = 4
ou
- 5x + 1 = 0
1 = 5x
1/5 = x