Bonjour pourriez vous m'aider s'il vous plaît Rendre les fractions suivantes irréductibles : 4/8 5/35 15/30 10/100 52/91 75/100 468/180 60/100 216/948 1620/1350

Bonjour,

4/8 =1/2

5/35=1/7

15/30 = 1/2

10/100 =1/10

52/91 = 4/7 ( divisé par 13)

75/100= 15/20= 3/4

468/180 = 234/90= 117/45= 39/15= 13/5

60/100 = 6/10= 3/5

216/948 = 108/ 474 = 54/237 = 18/79

1620/1350​ = 162/135 = 54/45= 18/15 = 6/5

Salut !

4/8 = (4×1)/(4×2) = 1/2

5/35 = (5×1)/(5×7) = 1/7

15/30 = (15×1)/(15×2) = 1/2

10/100 = (10×1)/(10×10) = 1/10

52/91 = (13×4)/(13×7) = 4/7

75/100 = (25×3)/(25×4) = 3/4

468/180 = (36×13)/(36×5) = 13/5

60/100 = (20×3)/(20×5) = 3/5

216/948 = (12×18)/(12×79) = 18/79

1620/1350 = (270×6)/(270×5) = 6/5